I have a hive table as below:
+----+---------------+-------------+
| id | name | partnership |
+----+---------------+-------------+
| 1 | sachin sourav | first |
| 2 | sachin sehwag | first |
| 3 | sourav sehwag | first |
| 4 | sachin_sourav | first |
+----+---------------+-------------+
In this table I need to replace strings such as "sachin" with "ST" and "Sourav" with "SG". I am using following query, but it is not solving the purpose.
Query:
select
*,
case
when name regexp('\\bsachin\\b')
then regexp_replace(name,'sachin','ST')
when name regexp('\\bsourav\\b')
then regexp_replace(name,'sourav','SG')
else name
end as newName
from sample1;
Result:
+----+---------------+-------------+---------------+
| id | name | partnership | newname |
+----+---------------+-------------+---------------+
| 4 | sachin_sourav | first | sachin_sourav |
| 3 | sourav sehwag | first | SG sehwag |
| 2 | sachin sehwag | first | ST sehwag |
| 1 | sachin sourav | first | ST sourav |
+----+---------------+-------------+---------------+
Problem: My intention is, when id = 1, the newName column should bring value as "ST SG". I mean it should replace both strings.
You can nest the replaces:
select s.*,
replace(replace(s.name, 'sachin', 'ST'), 'sourav', 'SG') as newName
from sample1 s;
You don't need regular expressions, so just use replace()
.