SPARQL - Query based on some property

Question

I want to get all the pizza names which has cheese toppings but the result shows (_:b0) which is kind of an owl restriction following is my query

PREFIX pizza: <http://www.co-ode.org/ontologies/pizza/pizza.owl#>
SELECT ?X WHERE {
    ?X rdfs:subClassOf* [
        owl:onProperty pizza:hasTopping ;
        owl:someValuesFrom pizza:CheeseTopping
    ]
}

using Pizza ontology from stanford

Answer 1

This works (Without reasoning enabled)

 PREFIX pizza: <http://www.co-ode.org/ontologies/pizza/pizza.owl#>
 SELECT ?X ?topping WHERE {
     ?X rdfs:subClassOf ?Y .  
     ?Y owl:someValuesFrom ?topping .
     ?topping rdfs:subClassOf* pizza:CheeseTopping
 } 
 ORDER BY ?X

Some are listed more than once as they could contain more than one CheeseTopping. To remove duplicates:

 PREFIX pizza: <http://www.co-ode.org/ontologies/pizza/pizza.owl#>
 SELECT DISTINCT ?X WHERE {
        ?X rdfs:subClassOf ?Y .  
        ?Y owl:someValuesFrom ?topping .
        ?topping rdfs:subClassOf* pizza:CheeseTopping
 }
 ORDER BY ?X

This works if you enable a reasoner:

PREFIX pizza: <http://www.co-ode.org/ontologies/pizza/pizza.owl#>
SELECT DISTINCT ?X WHERE {
    ?X rdfs:subClassOf pizza:CheeseyPizza
}

Ref: Used the pizza ontology from here: http://protege.stanford.edu/ontologies/pizza/pizza.owl