I've got some code that creates an object from a formula and saves the call for future use, as so:
create_obj <- function(formula, data) {
obj <- list()
# Populate obj with whatever we're interested in
# ...
# Save call for future use
obj$call <- match.call()
obj
}
obj <- create_obj(time ~ sex, data)
If I then bootstrap data
I can easily build the model on the new dataset:
data <- data[sample(1:nrow(data), replace=T), ]
new_obj <- eval(obj$call)
However, if I have the formula saved in a variable and I pass the object into a new environment this won't work:
do_stuff <- function(object, newdata) {
data <- newdata[sample(1:nrow(newdata), replace=T), ]
new_object <- eval(object$call)
}
main <- function() {
my_form <- time ~ sex
obj2 <- create_obj(my_form, data)
# obj2$call: 'create_obj(formula = my_form, data = data)'
do_stuff(obj2, data)
}
Error: object my_form
not found.
How can I have it so that obj$call
saves time~sex
rather than myform
? Otherwise I need to pass the formula itself around rather than just the object, limiting the practicality.
The above example isn't reproducible but you can see the same thing with a standard lm
call.
EDIT: I've solved the problem, see the accepted answer.
I've solved it by having the constructor function modify the call by evaluating the constant argument in the local environment:
create_obj <- function(formula, data) {
obj <- list()
# Populate obj with whatever we're interested in
# ...
# Save call for future use
func_call <- match.call()
func_call$formula <- eval(formula)
# obj_call is now: create_obj(formula=time~sex, data=data)
obj$call <- func_call
obj
}