It's possible that give std::vector<T>
e.g to function by forwarding reference?
I know that
template<typename T>
void f(const std::vector<T>&&){} // is rvalue
template<typename T>
void f(const std::vector<T>&){} // is lvalue
but how I can make function for lvalue and rvalue (with std::vector as parametr)?
I think you want
// traits for detecting std::vector
template <typename> struct is_std_vector : std::false_type {};
template <typename T, typename A>
struct is_std_vector<std::vector<T, A>> : std::true_type {};
template<typename T>
std::enable_if_t<is_std_vector<std::decay_t<T>>::value>
f(T&&); // Take any std::vector