rendering template to real html using preg_replace

Question

I want to replace template with HTML code, and it worked good, but the problem is that I use a php code inside the rendered HTML, and it can't run just printed like a string. this is the code:

$template = '[text required id="first_name" label="First Name"]';

$pattern = ['/^\[([a-z]+)\s{1,}(required)?\s{1,}(?:id|label)="([^"]+)"\s{1,}(?:id|label)="([^"]+)"\s{0,}\]/im'];

$replacement = ['<label for="$3">$4 ($2)</label>
<input type="text" name="$3" id="$3" 
<?php if( !empty($data["$3"]) ) { echo \'value="{$data[\"$3\"]}"\'; }?> />'];

$output = preg_replace($pattern, $replacement, $template);

echo $output;

And this is the output:

and this is the source of the output:

Thank you in advance.

Answer 1

This is the answer

<?php

$template = '[text required id="first_name" label="First Name"]';



$pattern = ['/^\[([a-z]+)\s{1,}(required)?\s{1,}(?:id|label)="([^"]+)"\s{1,}(?:id|label)="([^"]+)"\s{0,}\]/im'];

$replacement = ['<label for="$3">$4 ($2)</label>
<input type="text" name="$3" id="$3" '. get_data("$3") .' />'];


$output = preg_replace($pattern, $replacement, $template);


echo $output;


function get_data($index){
   if( !empty($data[$index]) ) { 
      echo 'value="{$data[$index]}"'; 
   }
}