Getting StackOverflow error and why?

Question

Why I am getting StackOverflowError at line 11. The line that I am getting error: System.out.println(new JavaInnerClass().callInnerClassMethod(animalQuantity));

Here is the full code:

public class Dog extends Animal {
private String animalName;
private int animalQuantity;

public Dog(String animalName, int animalQuantity) {
    animalName(animalName);
    quantity(animalQuantity);
    // JavaInnerClass.tempDog name = new JavaInnerClass.tempDog();
    // System.out.println(name.totalQuantity(animalQuantity));
    System.out.println(new JavaInnerClass().callInnerClassMethod(animalQuantity));
}

@Override
public String animalName(String animalName) {
    this.animalName = animalName;
    return animalName;
}

@Override
public int quantity(int animalQuantity) {
    this.animalQuantity = animalQuantity;
    return animalQuantity;
}

}

the JavaInnerClass:

public class JavaInnerClass {

Dog[] dog = { new Dog("Husky", 90), new Dog("Boxer", 100) };

tempDog temp = new tempDog();

public static class tempDog {

    public int totalQuantity(int quantity) {
        return quantity + 200; // assuming a statement
    }

}

public int callInnerClassMethod(int quantity) {
    return temp.totalQuantity(quantity);
}

public static void main(String[] args) {
    new JavaInnerClass();
}

}

Answer 1

The JavaInnerClass constructor invokes the Dog constructor that invokes the JavaInnerClass constructor that invokes the Dog constructor ... and so on...

---

Look at the JavaInnerClass constructor.

It initializes the array field dog :

Dog[] dog = { new Dog("Husky", 90), new Dog("Boxer", 100) };

But what does the Dog constructor ?
It creates an instance of JavaInnerClass :

public Dog(String animalName, int animalQuantity) {
     ...
    System.out.println(new JavaInnerClass().callInnerClassMethod(animalQuantity));
}

And all that goes on until the stackoverflow.