I've come across the problem of maintaining a state throughout a map operation several times. Imagine the following task:
Given a List[Int], map each element to the sum of all preceding elements and itself.
So 1,2,3 becomes 1, 1+2, 1+2+3.
One solution I've come up with is:
scala> val a = 1 to 5
a: scala.collection.immutable.Range.Inclusive with scala.collection.immutable.Range.ByOne = Range(1, 2, 3, 4, 5)
scala> a.foldLeft(List(0)){ case (l,i) => (l.head + i) :: l }.reverse
res3: List[Int] = List(0, 1, 3, 6, 10, 15)
But somehow I feel that there has to be a simpler solution.
You're trying to compute the sequence of partial sums.
The general operation for computing such accumulations is not fold
but scan
, though scan
is expressible through fold
in the way you showed (and fold
is actually the last element of the list produced by scan
).
scala> List(1,2,3).scanLeft(0)(_ + _)
res26: List[Int] = List(0, 1, 3, 6)