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pythonpython-3.xclipping

Pythonic way to limit ranges on a variable?


Is there a better way to do this?

if a > 1:
    a = 1
if a < 0:
    a = 0

I was thinking of using a function because I have a lot of these in my code, Was curious if there was a shorter comprehensible way to do it.


Solution

  • What you describe is usually called clipping. There are several ways to do clipping.

    Library (numpy)

    You can use numpy.clip for that:

    numpy.clip(a, a_min, a_max, out=None)

    So:

    import numpy
    
    numpy.clip(x,0,1)
    

    Although since function calls in Python are expensive, and numpy usually processes data in batch, for a single value it will result in computational overhead.

    For example:

    >>> x = -2.5
    >>> numpy.clip(x,0,1)
    0.0
    >>> x = 2.5
    >>> numpy.clip(x,0,1)
    1.0
    >>> x = 0.5
    >>> numpy.clip(x,0,1)
    0.5
    

    Usually you use numpy to perform operations on (large) matrices, for instance if you have to process a 1000x1000 matrix, than using numpy will definitely pay off.

    Pure Python

    A pure python approach can be obtained with:

    max(0,min(1,x))
    

    But here you have two calls, as a result, it will be slower than using if statements.

    Finally if you stick with the if-code, you can optimize it a tiny bit by using an elif:

    if x < 0:
        x = 0
    elif x > 1:
        x = 1
    

    Or a more generic function:

    def clip(x,min,max):
        if x < min:
            return min
        elif x > max:
            return max
        return x