py2neo execute cypher to find path

Question

i use py2neo to find get path ,my function like this :

-----------------------my funciton -----------------

def findrelationall1(graph_db,startmobile,endmobile):
    querystring='''MATCH(catelyn:Person {usernbr:%s}), (drogo:Person {usernbr:%s})
MATCH p=(catelyn)-[*..100]-(drogo)
RETURN p'''
    result=graph_db.run(querystring1)
    for x in result :
        dic1=dict(x)
        print dic1.values()

---

return is :

[(c0d4730)-[:a1_a2_201705 {count:4}]->(bf795f0)<-[:b1_b2_201705 {count:4}]-(ae68e9e)]

what "(c0d4730) " is ? a node ? how can i use this value to return a node and property ?

Answer 1

I think it is the internal id. Try from py2neo import remote remote(node)._id
See How to get automatic node ID from py2neo?