The pause()
function blocks until a signal arrives.
Assuming the process got a signal and pause() returned, does the signal handler will be executed before the code that follows the pause()
call, or the result is unexpected?
Example:
void sigusr1_handler()
{
// .. handler code
}
void main()
{
// .. bind handler to SIGUSR1
pause(); // wait for SIGUSR1
// some more code
}
Does "some more code" will always be executed after sigusr1_handler()
has finished, or there is a race condition? If so, what is the solution?
I cannot think of anything besides busy-waiting, but then the pause won't be needed at all..
Citing from the man page for pause(2):
pause() returns only when a signal was caught and the signal-catching function returned. In this case, pause() returns -1, and errno is set to EINTR.
You can be sure that your signal handler runs before some more code
.