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cpointersputs

Unable to understand a pointer statement

I am doing a ctf problem and there is a line i can't understand.

int  (*fp)(char *)=(int(*)(char *))&puts, i;

Can anyone explain me what does this mean?

Solution

  • fp is a pointer

    (*fp)

    to a function

    (*fp)(

    that accepts 1 argument of type char

    (*fp)(char)

    and returns a value of type int

    int (*fp)(char)

    The pointer is initialized with the address of puts after a mostly redundant conversion.

    int  (*fp)(char *)=(int(*)(char *))&puts
int  (*fp)(char *)=(int(*)(char *))puts // & redundant
int  (*fp)(const char *)=puts

    The object i is not initialized. It has type int

    int  (*fp)(char *)=(int(*)(char *))&puts, i;