Are multiple operations for string formatting allowed in Python?

Could be a basic one:

I am just trying to do multiple operations on one of the key in a dictionary with encoding the first element of the key, splitting it further based on a character and also joining with another string as below:

images_list["RepoTag"] = image["RepoDigests"][0].encode("utf-8").split("@")[0] + ":none"

Code snippet in which I am doing the above formatting:

from django.http import JsonResponse
from django.views.decorators.http import require_http_methods
import requests

@require_http_methods(["GET"])
def images_info(request):
    response = requests.get("http://127.0.0.1:6000/images/json")
    table = []
    images_list = {}
    for image in response.json():
        try:
            images_list["RepoTag"] = image["RepoTags"][0].encode("utf-8")
        except TypeError:
            images_list["RepoTag"] = image["RepoDigests"][0].encode("utf-8").split("@")[0] + ":none"
        images_list["Id"] = image["Id"].encode("utf-8")[7:19]
        table.append(images_list)
        images_list = {}

    return JsonResponse(table,safe=False)

Can someone tell me whether is it the right way to do these many operations in a single line? or in another way Does it follows the python standards ?

If not does python standards suggest any limited operations in a single line or so?

Reason for asking this is that the number of characters should not exceed 79 characters as per pep-8.

Solution

There's nothing wrong with chaining a few string operations together. If you want to keep it within the 80-character line, just add some parentheses:

images_list["RepoTag"] = (
    image["RepoDigests"][0].encode("utf-8").split("@")[0] + 
    ":none")

or use str.format() to provide those same parentheses:

images_list["RepoTag"] = '{}:none'.format(
    image["RepoDigests"][0].encode("utf-8").split("@")[0])

You could, otherwise, trivially use a local variable:

first_digest = image["RepoDigests"][0].encode("utf-8")
images_list["RepoTag"] = '{}:none'.format(first_digest.split("@")[0])