Running a Simple Falcon App

Question

I've a simple falcon app straight from the getting started example

import falcon
import json


class QuoteResource:
    def on_get(self, req, resp):
        """Handles GET requests"""
        quote = {
            'quote': 'I\'ve always been more interested in the future than in the past.',
            'author': 'Grace Hopper'
        }

        resp.body = json.dumps(quote)


api = falcon.API()
api.add_route('/quote', QuoteResource())

The code is in a file called manage.py

When I try to run gunicorn manage:app This is what I get

2017-06-04 20:47:18 -0700] [2370] [INFO] Starting gunicorn 19.7.1
[2017-06-04 20:47:18 -0700] [2370] [INFO] Listening at: http://127.0.0.1:8000 (2370)
[2017-06-04 20:47:18 -0700] [2370] [INFO] Using worker: sync
[2017-06-04 20:47:18 -0700] [2373] [INFO] Booting worker with pid: 2373
Failed to find application: 'manage'
[2017-06-04 20:47:18 -0700] [2373] [INFO] Worker exiting (pid: 2373)
[2017-06-04 20:47:18 -0700] [2370] [INFO] Shutting down: Master
[2017-06-04 20:47:18 -0700] [2370] [INFO] Reason: App failed to load.

What am I doing wrong here?

Answer 1

Not sure whether it is a typo or because of misunderstanding but you should start the application this way:

gunicorn manage:api

But not gunicorn manage:app

The manage:api option tells to invoke the api object defined in your manage.py module. Otherwise you need to rename api variable to app in your code.

Then you can check that application is running by accessing the following url:

http://localhost:8000/quote

By default the port should 8000 but you need to check it when gunicorn starts. It should be something like this:

[INFO] Listening at: http://127.0.0.1:8000