Cout starts printing at start of line when given a string

Question

I have a vector of strings in C++, named lines.

This line

std::cout << "First line: >" << lines[0] << "<" << std::endl; 

prints ">irst line: >string_here" instead of "First line: >string_here<".

Why does cout start printing at the start of the current line after the string, and how can I resolve it? I also tried to flush after every cout but result was the same.

This is a full code that ilustrates my problem, BEFORE it was solved:

#include <iostream>
#include <vector>
#include <string.h>

std::vector<std::string> parse(char *buffer, const char *delimiter) {
    std::string buff(buffer);
    size_t pos = 0;
    std::string part;
    std::vector<std::string> parts;
    while ((pos = buff.find(delimiter)) != std::string::npos) {
        part = buff.substr(0, pos);
        parts.push_back(part);
        buff.erase(0, pos + 1);
    }

    parts.push_back(buff);

    return parts;
}

int main() {
    char *s;
    s = strdup("Many lines\r\nOf text");

    std::cout << s << std::endl;  // this should print the string how it is

    std::vector<std::string> lines;
    lines = parse(s, "\n");  // parsing the string, after "\n" delimiter
    // that was the problem, I should have parsed after "\r\n"

    std::cout << "First line: >"<< lines[0] << "<" << std::endl;  // output
}

Answer 1

It's impossible to be sure without the full content of lines[0], but my (educated) guess would be that lines[0] ends with \r, the carriage return character, so everything printed after lines[0] is printed a the beginning of the line.