I need to convert time intervals in the format %H:%M:%S (class = factor) to class = difftime. I am currently using as.difftime() to do this, but it returns NA when the hour value is > 23.
TimeElapsed_raw = as.factor(c("03:59:59", "21:00:00", "01:03:46", "44:00:00", "24:59:59"))
TimeElapsed = as.difftime(as.character(TimeElapsed_raw), format = "%H:%M:%S")
TimeElapsed
Time differences in hours
[1] 3.999722 21.000000 1.062778 NA NA
I have the same problem whether or not I include the format statement in as.difftime():
as.difftime("65:01:17")
Time difference of NA secs
But this works:
as.difftime(65.1, units = "hours")
Time difference of 65.1 hours
I've also tried using the lubridate as.duration() function, but the values it calculates seem nonsensical.
as.duration(TimeElapsed_raw)
[1] "2s" "3s" "1s" "5s" "4s"
Any help would be appreciated!
You could first change the format of your data to xH xM xS which is understood by the duration function in lubridate:
x=gsub("(^\\d{2}):(\\d{2}):(\\d{2})$","\\1H \\2M \\3S",as.character(TimeElapsed_raw))
[1] "03H 59M 59S" "21H 00M 00S" "01H 03M 46S" "44H 00M 00S" "24H 59M 59S"
And then apply duration:
duration(x)
[1] "14399s (~4 hours)" "75661s (~21.02 hours)" "3826s (~1.06 hours)"
[4] "158461s (~1.83 days)" "89999s (~1.04 days)"
Otherwise, using as.difftime, you could first split your data into hours, minutes and seconds and feed each one seperately to as.difftime:
v=lapply(strsplit(TimeElapsed_raw,":"),function(x) {as.difftime(as.numeric(x[1]),units="hours")+as.difftime(as.numeric(x[2]),units="mins")+as.difftime(as.numeric(x[3]),units="secs")})
[[1]]
Time difference of 14399 secs
[[2]]
Time difference of 75600 secs
[[3]]
Time difference of 3826 secs
[[4]]
Time difference of 158400 secs
[[5]]
Time difference of 89999 secs
If you want to convert the list to a vector, make sure to reconvert it to difftime afterwards as unlist loses the class.
v=as.difftime(unlist(v),unit="secs")