I have been able to figure out how to get the name of the attached file in an email. i am just stuck after that. I don't know what to do after that, I have tried using os.path.join
which just gives the path i want to download the folder to and joins it with the filename. Please suggest something. Thanks.
m = imaplib.IMAP4_SSL('outlook.office365.com',993)
m.login("UN", "PW")
m.select("Inbox")
typ, msgs = mail.search(None, '(SUBJECT "qwerty")')
msgs = msgs[0].split()
for emailid in msgs:
resp, data = mail.fetch(emailid, "(RFC822)")
email_body = data[0][1]
m = email.message_from_bytes(email_body)
if m.get_content_maintype() != 'multipart':
continue
for part in m.walk():
if part.get_content_maintype() == 'multipart':
continue
if part.get('Content-Disposition') is None:
continue
filename = part.get_filename()
print(filename)
Following the sample from this link you can set the path when using the open function. (raw string by prefixing the string with r)
fp = open(r'c:\tmp\folder\' + filename, 'wb')
fp.write(part.get_payload(decode=True))
fp.close()
print '%s saved!' % filename