Unexpected output in C program

Question

I run the following C program

#include <stdio.h>

int main() {
    int x = 5, y = 6, z = 3, i;
    i = y > x > z;
    printf("%d\n", i);
}

and get the output as 0. Again, when I run

 #include <stdio.h>

 int main() {
     int x = 5, y = 6, z = 3, i;
     i = y > x && x > z;
     printf("%d\n", i);
 }

I get output as 1. Can anyone explain the logic behind this?

Answer 1

i = y > x > z;

In first example, associativity of > operator left to right, So, First parsed y > x and gives boolean result.

y > x = 6 > 5 = True

then,

1(True) > 3 = False

So, output 0.

In Second,

i = y > x && x > z;

> operator higher precedence then && operator. So, first parsed y > x and if condition True, then check x > z.