I need to detect if a command have sudo
command in one of it's sub commands, so far I have this:
public function split_command($command) {
// this regex is not perfect but work
$separators = "/(?:\"[^\"\\\\]*(?:\\\\[\S\s][^\"\\\\]*)*\"|'[^'\\\\]*(?:\\\\[\S\s][^'\\\\]*)*')(*SKIP)(*F)|(\s+(?:&&|\|{1,2}|;)\s+)/";
$flags = PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE;
return preg_split($separators, $command, null, $flags);
}
public function have_sudo($command) {
$re = "!^(sudo|" . shell_exec("which sudo") . ")!";
foreach ($this->split_command($command) as $part) {
if (preg_match($re, trim($part))) {
return true;
}
}
}
but if fail is command look like this: echo `sudo whoami`
. How can I parse the command to get list of sub shells.
it should also work for commands like this:
$(some command; `other command (different command) $(some command)`)
it should return array:
["some command; `other command (different command) $(some command)`",
"`other command (different command) $(some command)",
"different command", "some command"]
so I can call have_sudo recursively on each element of the array the other option is to return most outer subshells from command.
I've created a parser:
public function get_subshells($command) {
$re = '/(\$\(|\(|\)|`)/';
$parts = preg_split($re, $command, -1, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);
$subshells = array();
$backtick = false;
$stack = array();
foreach ($parts as $part) {
if (preg_match($re, $part)) {
if ($part == "`") {
$backtick = !$backtick;
}
if ($backtick || preg_match("/\(/", $part)) {
$stack[] = array('tag' => $part, 'content' => '');
} else {
$last = array_pop($stack);
$subshells[] = preg_replace('/^(\$\(|\(|`)/', '', $last['content']);
}
}
if (count($stack) > 0) {
foreach ($stack as &$subshell) {
$subshell['content'] .= $part;
}
}
}
return array_reverse($subshells);
}