How to condense, i.e. eliminate redundancies from, the following data:
code: GB-ENG, jobs: 2673
code: GB-ENG, jobs: 23
code: GB-ENG, jobs: 459
code: GB-ENG, jobs: 346
code: RO-B, jobs: 9
code: DE-NW, jobs: 4
code: DE-BW, jobs: 3
code: DE-BY, jobs: 9
code: DE-HH, jobs: 34
code: DE-BY, jobs: 11
code: BE-BRU, jobs: 27
code: GB-ENG, jobs: 20
The output should be in this way:
GB-ENG, 3521
RO-B, 9
DE-NW, 4
DE-BW, 3
DE-HH, 34
DE-BY, 20
BE-BRU, 27
Described by 1 canonical representation of each code, i.e. DE-BY
, that would represent the sum total aggregated over the numbers that are associated with each instance of that code, e.g.:
code: DE-BY, jobs: 11
code: DE-BY, jobs: 9
becomes
DE-BY, 20
at the moment I'm creating that input with this Python script:
import json
import requests
from collections import defaultdict
from pprint import pprint
def hasNumbers(inputString):
return any(char.isdigit() for char in inputString)
# open up the output of 'data-processing.py'
with open('job-numbers-by-location.txt') as data_file:
# print the output to a file
with open('phase_ii_output.txt', 'w') as output_file_:
for line in data_file:
identifier, name, coords, number_of_jobs = line.split("|")
coords = coords[1:-1]
lat, lng = coords.split(",")
# print("lat: " + lat, "lng: " + lng)
response = requests.get("http://api.geonames.org/countrySubdivisionJSON?lat="+lat+"&lng="+lng+"&username=s.matthew.english").json()
codes = response.get('codes', [])
for code in codes:
if code.get('type') == 'ISO3166-2':
country_code = '{}-{}'.format(response.get('countryCode', 'UNKNOWN'), code.get('code', 'UNKNOWN'))
if not hasNumbers( country_code ):
# print("code: " + country_code + ", jobs: " + number_of_jobs)
output_file_.write("code: " + country_code + ", jobs: " + number_of_jobs)
output_file_.close()
it would probably be most efficient to include this functionality as part of that script but I've not been able to yet figure out how.
assuming the text is stored in a text file, this would work
infile = open('redundancy.txt','r')
a= infile.readlines()
print a
d={}
for item in a:
c=item.strip('\n')
b=c.split()
if b[1] in d :
d[b[1]]= int(d.get(b[1]))+eval((b[3]))
else:
d[b[1]]=b[3]
print d
it would give a result :
{'DE-BY,': 20, 'DE-HH,': '34', 'DE-BW,': '3', 'DE-NW,': '4', 'RO-B,': '9', 'GB-ENG,': 3521, 'BE-BRU,': '27'}