What's wrong with my C program? It's about pointer and selection sort

Question

What's wrong with my C program? the title is to sort n number from small to large, when i run it, everything goes fine but the number isn't been sorted. I just don't know how to solve that although i have thought for a long time.

Here is the code:

#include <stdio.h>
#include <time.h>
#include <stdlib.h>

void selection(int *a[], int n);
int main()
{
    int n;
    int i;
    scanf("%d", &n);
    int *a[n];
    int b[n];
    srand((int) time(0));
    for (i = 0; i < n; i++)
    {
        b[i] = ((int) (rand() % 100));
        a[i] = &b[i];
    }
    selection(a, n);
    return 0;
}

void selection(int *a[], int n)
{
    int i;
    int j;
    int position;
    int temp;
    for (i = 0; i < n - 1; i++)
    {
        position = i;
        for (j = i + 1; j < n; j++)
        {
            if (*a[i] > *a[j])
                position = j;
        }
        temp = *a[i];
        *a[i] = *a[position];
        *a[position] = temp;
    }
    for (i = 0; i < n - 1; i++)
        printf("%d\n", *a[i]);
}

Answer 1

I have found neither the quick sort nor the bubble sort in the presented code.

It seems you are trying to use the selection sort.

I think that the function can look the following way.

void selection_sort( int * a[], int n )
{
    int i;

    for ( i = 0; i < n; i++ )
    {
        int position = i;
        int j = i + 1;

        for ( ; j < n; j++ )
        {
            if ( *a[j] < *a[position] ) position = j;
        }

        if ( position != i )
        {
            int *temp = a[position];
            a[position] = a[i];
            a[i] = temp;
        }
    }

    for ( i = 0; i < n; i++ ) printf( "%d ", *a[i] );
    putchar( '\n' );
}