ActionPickerView get result

Question

I have a pickerView linked with a button when you click to the Button it will appears ..

my problem is : I don't know how to get the result and print it to the textFiled I created..

if I can make the result in the button name without needed to the text filed will be great !!

thats what I did so far :

import UIKit
import ActionSheetPicker_3_0


class ViewController2: UIViewController {

@IBOutlet weak var text1: UITextField!
@IBAction func ssss(_ sender: Any) {


    ActionSheetMultipleStringPicker.show(withTitle: "Multiple String Picker", rows: [
        ["One", "Two", "A lot"],
        ], initialSelection: [1],

           doneBlock: {


            picker, indexes, values in


            self.text1.text = ("\(values)")

            /**
            print("values = \(values)")
            print("indexes = \(indexes)")
            print("picker = \(picker)")
            return
**/

    },


           cancel: { ActionMultipleStringCancelBlock in return }, origin: sender)


}

Answer 1

I think you made a mistake with the variable name in the doneBlock while you are assigning the value to the text field. Also, check out the initialSelection parameter. You have provided [1] which will select the whole Array.

 ActionSheetMultipleStringPicker.show(
      withTitle: "Multiple String Picker", 
      rows: [["One", "Two", "A lot"]], 
      initialSelection: [1, 1],
      doneBlock: { picker, indexes, values in
        // self.text1.text = ("\(vslues)")
        // should be
        self.text1.text = ("\(values)")
      },
      cancel: { ActionMultipleStringCancelBlock in return }, 
      origin: sender)