Is there a way to get path/to/file with ls + awk, sed, grep or similar tools?

I'd like to recursively search a directory, and output:

Filename Date Path Size

I got everything but Path...which is a $$$$buster....

Here's my command so far:

ls -lThR {DIRECTORY_NAME_HERE} | awk '/^-/ {print $10 " " $6 " " $7 " " $8 " " $5}'

I wish there was a way to combine that command with:

find ./{DIRECTORY_NAME_HERE} -type f

which just shows /path/to/filename itself...no other metadata afaik.

Any ideas...hopefully without needing a programming language?

EDIT: Here's the exact output I was looking for assuming file is 5 bytes:

myfile.txt Dec 2 10:58 /path 5

UPDATE: Here's the command I wound up with:

find ./{DIRECTORY_NAME_HERE} -type f -ls | 
while read f1 blocks perms blocks owner group size mon day third file; 
do echo `basename $file` `ls -lrt $file | tr -s " " | cut -d" " -f6-8` `dirname $file` `ls -lrt $file | tr -s " " | cut -d" " -f-5`; done

If someone can improve it, that'd be great, but this works...

Solution

Have you tried find ./delete -type f -ls (note the -ls -- that's the key :-) )? You should then be able to pipe the results through awk to filter out the fields you want.

Edit... Another way you could do it is with a while loop, e.g.:

find ./delete -type f -ls | while read f1 blocks perms blocks owner group size mon day third file
do
    echo `basename $file` `dirname $file`
done

and add the bits you need into that.