In Go, I'm trying to decode this XML into the "fileRetriever" struct. I only care about the file names:
<?xml version="1.0" encoding="ISO-8859-1" ?>
<FileRetriever>
<FileList>
<File name="Name1" />
<File name="Name2" />
</FileList>
</FileRetriever>
I think this code snippet is close, but I can't seem to see where I'm going wrong. It produces no errors, but also a zero-length list of file names:
import (
"encoding/base64"
"encoding/xml"
"fmt"
"net/http"
"golang.org/x/net/html/charset"
)
type fileRetriever struct {
Files []file `xml:"FileRetriever>FileList>File"`
}
type file struct {
Name string `xml:"name,attr"`
}
func Main(){
retrieve()
}
func retrieve()(retriever *fileRetriever){
req := ... //set up http.NewRequest()
client := &http.Client{}
rsp, err := client.Do(req)
if err != nil {
log.Fatal(err)
}
defer rsp.Body.Close()
decoder := xml.NewDecoder(rsp.Body)
decoder.CharsetReader = charset.NewReaderLabel
retriever = &fileRetriever{}
err = decoder.Decode(&retriever)
if err != nil {
fmt.Println(err)
}
return retriever, xTidx
}
The root element is automatically decoded into the value you pass to Decode
so you don't need to mention it in the Files
field tag.
So just change xml:"FileRetriever>FileList>File"
to xml:"FileList>File"
.