Search code examples
perlpathgenericsseparator

How can I get the directory (file path) separator in Perl?

In case of Java, we can get the path separator using 

System.getProperty("path.separator");

Is there a similar way in Perl? All I want to do is to find a dir, immediate sub directory. Say I am being given two arguments $a and $b; I am splitting the first one based on the path separator and joining it again except the last fragment and comparing with the second argument.

The problem is my code has to be generic and for that I need to know whats the system dependent path separator is?

Solution

  • If you really want to get the separator (using only Perl core modules):

    my $sep = File::Spec->catfile('', '');

    This joins two empty file names with the current system's separator, leaving only the separator.