Parsing unescaped HTML to HTML template in Go

I have created this really simple program for testing.

package main

import (
    "fmt"
    "github.com/microcosm-cc/bluemonday"
    "github.com/pressly/chi"
    "github.com/russross/blackfriday"
    "github.com/unrolled/render"
    "net/http"
)

func main() {
    r := chi.NewRouter()
    r.Get("/", homepageGET)
    http.ListenAndServe(":8080", r)
}

func homepageGET(w http.ResponseWriter, r *http.Request) {
    Renderer := render.New(render.Options{
        Directory:    "frontend",
        Extensions:   []string{".tmpl", ".html"},
        UnEscapeHTML: true,
    })
    unsafe := blackfriday.MarkdownCommon([]byte("**bolded text**"))
    markdownContent := bluemonday.UGCPolicy().SanitizeBytes(unsafe)
    fmt.Print(string(markdownContent))
    Renderer.HTML(w, http.StatusOK, "index", map[string]interface{}{
        "content": fmt.Sprintf(string(markdownContent))})
}

And then I have a HTML file containing nothing besides:

<body>
  {{ .content }}
</body>

The fmt.Print command prints "bolded text", whereas it's inserted into the HTML page as: "bolded text".

I believe it is related to escaped HTML, but for the unrolled/render package I configure it as unescaped.. I'd greatly appreciate any help getting the test program working (preferably together with unrolled/render).

Solution

In Go you can convert known safe html strings to the template.HTML type, and since unrolled/render uses Go's html/template to render html you should be able to use just that.

Renderer.HTML(w, http.StatusOK, "index", map[string]interface{}{
        "content": template.HTML(markdownContent),
})