find cout of specific day between two date php without using any loop?

Question

I need to find out count of a specific Day between two date. I can do this by using loop between two date, but if there is difference of 10 years(suppose) between date loop will run 10*365 times. Is any easier way to do this?
Thanks in advance

Answer 1

function countDays($day, $start, $end) {

$start = strtotime($start);
$end = strtotime($end);
$datediff = $end - $start;

$days =  floor($datediff / (60 * 60 * 24));


//get the day of the week for start and end dates (0-6)
$w = array( date('w', $start ), date('w', $end) );

//get partial week day count
if ($w[0] < $w[1])
{            
    $partialWeekCount = ($day >= $w[0] && $day <= $w[1]);
}else if ($w[0] == $w[1])
{
    $partialWeekCount = $w[0] == $day;
}else
{
    $partialWeekCount = ($day >= $w[0] 
    $day <= $w[1]); 
} 
//first count the number of complete weeks, then add 1 if $day falls in a partial week. 
return intval($days / 7) + $partialWeekCount; 

}

Function Call - countDays( 5, "2017-04-14", "2017-04-21")