How do you print the wrong python file name while serially running multiple python files in a directory?

Question

I am using the below python code to run multiple python files in a directory D:\PYTHON FILES using try except method. I need to print the name of the file that has failed to run.Please refer the codes below. Could anyone help me in view of this?

Please Note:

Please run this in DOS prompt and do not use IPython. Place all your python files including one corrupt file in the directory D:\PYTHON FILES

import os, glob
dir='D:\PYTHON_FILES'
os.chdir(dir)

files = glob.glob ('*.py');
for eachfile in files:
    try:
       os.system('python '+eachfile+'\n')
    except:
        print(eachfile + ' missed out')
    finally:
        print('======================')

Answer 1

The mentioned code requires some corrections, for example

import os, glob
dir_path = 'D:\PYTHON_FILES'
os.chdir(dir_path)

file_names = glob.glob('*.py')
for file_name in file_names:
    return_value = os.system('python {}'.format(file_name))
    if return_value != 0:
        print('{} missed out'.format(file_name))
print('=' * 24)

for more pythonic solution. The non-zero return value signs that there was some problems with the execution of the command of system function.