i am using tkinter to make a gui and have made various different buttons and now i have made all this i am unsure how to correctly make the first gui box close as the second one opens (sign_in function)
from tkinter import *
class login:
def __init__(self, master):
frame = Frame(master)
frame.grid()
self.button1 = Button(frame, text="signup", fg="green",command=self.sign_in)
self.button2 = Button(frame, text="sign in", fg="black",)
self.button3 = Button(frame, text="quit", fg="red", command=frame.master.destroy)
self.button1.grid(stick=W)
self.button2.grid(stick=W)
self.button3.grid(stick=W)
def sign_in(self):
frame = Frame()
frame.grid()
name = Label(root, text="Name: ")
password = Label(root, text="password: ")
entry1 = Entry(root)
entry2 = Entry(root)
name.grid(row=0, sticky=E)
password.grid(row=1, sticky=E)
entry1.grid(row=0, column=1)
entry2.grid(row=1, column=1)
c = Checkbutton(root, text="keep me logged in")
c.grid(columnspan=2, sticky="w")
root = Tk()
account=login(root)
root.mainloop()
Your code contains some indentation errors so I'll just go by your question.
when i click the button 'signup' it closes that gui and opens the next one
You can do so by first withdrawing your root window like this: root.withdraw()
which will hide your original window. Then create a Toplevel window like this: newWindow = tk.Toplevel(root)
to create a new window. You will just need to place these lines in the button command call.
Here's what you can change in the sign_in
note that I changed all the masters to frame
and not root
:
def sign_in(self):
root.withdraw()
frame = Toplevel(root)
name = Label(frame, text="Name: ")
password = Label(frame, text="password: ")
entry1 = Entry(frame)
entry2 = Entry(frame)
name.grid(row=0, sticky=E)
password.grid(row=1, sticky=E)
entry1.grid(row=0, column=1)
entry2.grid(row=1, column=1)
c = Checkbutton(frame, text="keep me logged in")
c.grid(columnspan=2, sticky="w")