Consider:
function OuterFunc: integer;
function InnerFunc: integer;
begin
// Here I'd like to access the OuterFunc.Result variable
// for both reading and writing its value
OuterFunc.Result := OuterFunc.Result + 12;
end;
begin
end;
Is there a native syntax to access the OuterFunc Result variable inside InnerFunc? Or is the only way to do this to pass it like a parameter, as in the following?
function OuterFunc: integer;
function InnerFunc(var outerResult: integer): integer;
begin
end;
var
i: integer;
begin
i := InnerFunc(Result);
end;
You can assign result to functions by assigning to the function name, which actually was the original way in Pascal:
function MyFunc: integer;
begin
MyFunc := 2;
// is equal to the following
Result := 2;
end;
So in your case you can write
function OuterFunc: integer;
function InnerFunc: integer;
begin
OuterFunc := 12;
end;
begin
end;
Beware however, that using the function name in a statement block anyware else than on the left side of the assignment operator results in a recursive call, and is therefore different from how the predefined Result
works.
In other words, you can not access a previously set value of OuterFunc
from within InnerFunc
. You would need to use e.g. a local variable in the outer scope defined before InnerFunc
to be accessible also from InnerFunc:
function OuterFunc: integer;
var
OuterResult: integer;
function InnerFunc: integer;
begin
OuterResult := 0;
OuterResult := OuterResult + 12;
end;
begin
Result := OuterResult;
end;
For more details refer to Function Declarations
in the documentation.