What is the best way to check if a variable is a list?

I found this 3 ways to check it, but I don't know which of them is the best:

x = ['Bla', 'Bla', 'Bla', 'etc']

if isinstance(a, list): print('Perfect!')
if type(a) is list:     print('Incredible!')
if type(a) == type([]): print('Awesome!')

Which of these is better?

Also, Can I use these ways to check whether an x is a string, tuple, dictionary, int, float, etc? If this is possible, in the first two methods do I have to convert a list to a tuple, string, dictionary, int, float, etc (no?), but in the third? I have to use (), {}, '', and what more for int and float?

Solution

These all express different things, so really it depends on exactly what you wish to achieve:

isinstance(x, list) check if the type of x is either list or has list as a parent class (lets ignore ABCs for simplicity etc);
type(x) is list checks if the type of x is precisely list;
type(x) == list checks for equality of types, which is not the same as being identical types as the metaclass could conceivably override __eq__

So in order they express the following:

isinstance(x, list): is x like a list
type(x) is list: is x precisely a list and not a sub class
type(x) == list: is x a list, or some other type using metaclass magic to masquerade as a list.