I've been trying to write a simple script in order to upload 200+ links to a website I'm working in (I have poor knowledge on python and even poorer in HTML, of course I wasn't working as a web developer, I just need to upload these links).
Well, the situation I'm in is the following: I am using Splinter(therefore, Python) in order to navigate in the website. Certain section titles of this website will be compared with values I have in a .csv table.
For instance, in this screenshot, I am looking for this link /admin/pages/5, and I would like to compare the link's title (Explorar subpáginas de 'MA111 - Cálculo I') with my .CSV table. The problem is the link's title doesn't appear in the website.
To find the link I would guess that I should use find_by_xpath(), but I don't know how to do it. I would guess it's something like this link.
I would appreciate any help! I hope I have made myself clear.
You first need to define how are you detecting that url, so for example, "it is always to the right of certain button", or "it is the second row in a table", that way you can build the respective xpath (which is a path to follow inside the DOM.
I am not entirely sure, but this could give you the solution
url = browser.find_by_xpath('//td[@class="children"]/a')[0]['href']
if you are finding a tag by the link name for example, try this:
url = browser.find_by_xpath('//a[contains(@title, "MA111 - Cálculo I")]')[0]['href']
If you check there, the xpath says "find in the entire DOM // a tag named a which contains "MA111 - Cálculo I" in the title attribute.