I don't know how to start but what I am trying to do is to scan a directory which contains video files and send the ids to another php called video.php to display the video. However when there is a subfolder I want to identify it and send its unique id to video.php to perform different action. I don't know how to identify the subfolders.
main.php
$dir = "./media/";
if ($handle = opendir($dir)) {
while (false !== ($file = readdir($handle))) {
if ($file != "." && $file != "..") {
$list[] = $file;
}
}
closedir($handle);
}
krsort($list);
foreach($list as $file) {
$thelist .= '<div class="button"><div class="item">
<a href="video.php?id='.$file.'">
<img src="play.png"
alt="VIDEO Thumbnail"style="width:250;height:150;border:0;">
<span class="caption">'.$file.'</span> </a></div></div>';
}
video.php
<?php
$id = $_GET['id'];
?>
<video class='center' controls autoplay>
<source src="./media/<?php echo $id; ?>" type="video/mp4">
<source src="./media/<?php echo $id; ?>" type="video/ogg">
Your browser does not support the video tag.
</video>
I am not exactly sure what you are asking, but I'll take a stab anyhow. Please offer specific feedback if I am not providing a suitable solution.
main.php
$dir="./media/";
if($handle=opendir($dir)){
while(false!==($file=readdir($handle))){
if($file!="." && $file!=".."){
if(is_dir("$dir/$file")){ // <-- I think this is the part you are looking for
$dirs[]=$file;
}else{
$files[]=$file;
}
}
}
closedir($handle);
}
krsort($files); // not sure why you want to sort DESC
foreach($files as $file){
$thelist.="<div class=\"button\"><div class=\"item\"><a href=\"video.php?id=$file\"><img src=\"play.png\" alt=\"VIDEO Thumbnail\" style=\"width:250;height:150;border:0;\"><span class=\"caption\">$file</span>/a></div></div>";
}
krsort($dirs); // not sure why you want to sort DESC
foreach($dirs as $dir){
// provide links to video.php with directory id $dir
}
video.php
$fileid=$_GET['fileid']; // sanitize this
$dirid=$_GET['dirid']; // sanitize this
if($fileid){
echo "<video class=\"center\" controls autoplay>";
echo "<source src=\"./media/$fileid\" type=\"video/mp4\">";
echo "<source src=\"./media/$fileid\" type=\"video/ogg\">";
echo "Your browser does not support the video tag.";
echo "</video>";
}elseif($dirid){
// do what you like with $dirid
}else{
// default action when no id is provided
}