Can class type be deduced from pointer to member function template parameter

Question

Is it possible to deduce the type of the class T from its pointer to memmber T::*f as shown below.

struct Foo
{
    void func(){}
};

template<typename T, void (T::*f)()>
void bar()
{
}

int main()
{
    bar<Foo,Foo::func>();
    // bar<Foo::func>(); // Desired
}

Answer 1

In C++17, you will be allowed to write

template<auto M>
void bar();

Which allows

bar<&Foo::func>();