Format float\double numbers to CString with zero filling and preset number of digits

Question

I am looking for a simple method to format the following float\double numbers to a CString.
I was hoping to use CString.Format(), but alternatives are welcome as well, as long as it ends up being a CString.

3.45
112.2

To the following format:

00003450
00112200

Notice there should be no decimal point.
Can this be done simply, if so how?

Answer 1

CString myString;
myString.Format(_T("%08d"), static_cast<int>(num * 1000.0 + 0.5));

Alternatively:

//...
#include <sstream>
#include <iomanip>

using namespace std;

//...
ostringstream s;
s << setfill('0') << setw(8) << static_cast<int>(num * 1000.0 + 0.5);

CString myString(s.str().c_str());
//...

Refs:

1. CString::Format
2. printf