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phpoperator-precedence

PHP conditional assignment

Found an interesting piece of code in Symfony core

if ('' !== $host = $route->getHost()) {
    ...
}

The precedence of !== is higher than the = but how does it work logically? The first part is clear but the rest?

I've created a little sample but it's still not clear: sample

Solution

  • The point is: The left hand side of an assignment has to be an variable! The only possible way to achieve this in your example is to evaluate the assignment first - which is what php actually does.

    Adding parenthesis makes clear, what happens

    '' !== $host = $route->getHost()
// is equal to
'' !== ($host = $route->getHost())
// the other way wouldn't work
// ('' != $host) = $route->getHost()

    So the condition is true, if the return value of $route->getHost() is an non empty string and in each case, the return value is assigned to $host.

    In addition, you could have a look a the grammer of PHP

    ...
variable '=' expr |
variable '=' '&' variable |
variable '=' '&' T_NEW class_name_reference | ...

    If you read the operator precendence manual page carefully, you would see this notice

    Although = has a lower precedence than most other operators, PHP will still allow expressions similar to the following: if (!$a = foo()), in which case the return value of foo() is put into $a.