traverse bash array including empty elements

Question

array=('' '' 2 4); for f in ${array[@]}; do echo a; done
a
a

I expected four "a" rows here as there are 4 elements of array

$ echo ${#array[@]}

4

Answer 1

You must quote the variable for correct using:

array=('' '' 2 4); for f in "${array[@]}"; do echo a; done

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