Execution order of try, catch and finally block

Question

Suppose I have some C# code like this:

try {
    Method1();
}
catch(...) {
    Method2();
}
finally {
    Method3();
}
Method4();
return;

My question is, provided no exception is thrown, will Method3() be executed before Method4(), or is it that the finally block is only executed before a return, continue or break statement?

Answer 1

Yes, the finally block of the try-catch will be executed in order as you would expect, and then execution will proceed onto the rest of the code (after completing the entire try-catch-finally block).

You can think of the entire try-catch-finally block as a single component that would function just like any other method call would (with code being executed before and after it).

// Execute some code here

// try-catch-finally (the try and finally blocks will always be executed
// and the catch will only execute if an exception occurs in the try)

// Continue executing some code here (assuming no previous return statements)

Example

try 
{
    Console.WriteLine("1");
    throw new Exception();
}
catch(Exception) 
{
    Console.WriteLine("2");
}
finally 
{
    Console.WriteLine("3");
}
Console.WriteLine("4");
return;

You can see an example of this in action here that yields the following output :

1
2
3
4