This is the Code and when i input a letter it would not display the line .matches instead i got an error but if i remove the parseFloat rec1 and remove the else if (rec1 < total) then the .matches line will display please help me how to do this thank you in advance
CashType c = new CashType(); c.setVisible(true);
c.jButton1.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed(java.awt.event.ActionEvent evt) {
String receive = c.jTextField1.getText();
float total = total("sellno"+SellNoCount.getText());
float rec1 = Float.parseFloat(receive); //this is line 1525
if(!receive.matches("[0-9]+")){
JOptionPane.showMessageDialog(null,"Enter a Valid Amount");
c.jTextField1.setText("");
}
else if(receive.equalsIgnoreCase("")){
JOptionPane.showMessageDialog(null,"Enter Amount");
}
else if(rec1 < total){
JOptionPane.showMessageDialog(null,"Insufficient Amount");
}
//ERROR
Exception in thread "AWT-EventQueue-0" java.lang.NumberFormatException: For input string: "asdasd"
at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:2043)
at sun.misc.FloatingDecimal.parseFloat(FloatingDecimal.java:122)
at java.lang.Float.parseFloat(Float.java:451)
at projectfinal.SellPage$32.actionPerformed(SellPage.java:1525)
From the error message, it look like you are entering "asdasd" to jTextField1. This value you are trying to parse to float. Float.parseFloat(string)
will throw a NumberFormatException if the String is not a numeric. In parseFloat()
method, the string parameter will be converted to a primitive float value.
You can check the value entered is numeric or not and then parse it to float.
float rec1 = 0;
if(isNumeric(receive)){
rec1 = Float.parseFloat(receive);
if(rec1 < total){
JOptionPane.showMessageDialog(null,"Insufficient Amount");
}
}else {
JOptionPane.showMessageDialog(null,"Enter a Valid Amount");
c.jTextField1.setText("");
}
The method is
public static boolean isNumeric(String s) {
return s.matches("[-+]?\\d*\\.?\\d+");
}