How do I "tee" variable number of times in a bash "for loop"?

Question

I understand I can:

ssh archive_server -l user -n "cat text.csv"|tee -a text1.csv|tee -a text2.csv|tee....|tee -a text10.csv

Is there a way to do it a a loop?

for i in `seq 1 10`; do
  echo $i
  tee ???
done

Answer 1

You don't need a loop. tee can be given multiple filename arguments, so just give all the output files at once:

cat text.csv | tee -a text{1..10}.csv

If the number of files is dynamic, you can use a loop in $() to insert the filenames into the command line:

cat text.csv | tee -a $(
    for i in $(seq 1 $filecount); do
        echo text$i;
    done)

Just make sure that you don't have any whitespace in the output filename prefix, as the spaces will be treated as argument delimiters.