I am making a simple Led program that will be turned into a library for my project. I have created four methods that will allow you to A) Setup as many Led pins as you want and make them as Outputs. B) Flash the Led lights at a customized time. C) Turn On Leds. D) Turn Off Leds. Everything is working if i just run the methods in the void loop(). For example:
Void loop(){
flashLed(pinNum, 2000);
turnOf(pinNum);
turnOn(pinNum);
}
If i run the above code it works fine, however it keeps looping as its obviously in a loop. So i decided to start the serial com by using Serial.begin(9600) in the setup(), and then testing for the serial com and used a switch case statement in order to appropriately implement these methods. What am i doing wrong here? i get no errors at all. When i type into the serial monitor nothing happens, i believe my logic is fine but that is why i am here. When anything is typed into the serial monitor, the code runs the default in the switch case statement and that is all. I have tried using while, if to no avail. Also tested the inverse of serial which would be !serial.available() Here is my code:
//Define the pin numbers
byte pinNum[] = {4, 3, 2};
void setup() {
//Setup the ledPins
ledSetup(pinNum);
Serial.begin(9600);
}
void loop() {
while(Serial.available() > 0){
//Read the incoming byte
byte ledStatus = Serial.read();
switch (ledStatus){
case 0:
turnOff(pinNum);
Serial.println("The Leds Have Been Turned Off");
break;
case 1:
turnOn(pinNum);
Serial.println("The Leds Have Been Turned On");
break;
case 2:
flashLed(pinNum, 1000); //This will make the Led blink for half a second
Serial.println("The Leds Will Begin Flashing");
break;
default:
flashLed(pinNum, 1000); //This will make the Led blink for half a second
break;
}
}
}
//Method to declare the pins as output
void ledSetup(byte ledPins[]){
for (int i = 0; i <= sizeof(ledPins); i++){
pinMode(ledPins[i], OUTPUT);
}
}
//Method to blink the Led light/lights
void flashLed(byte ledBlink[], int duration){
//Time is divided by two because it takes 2 seconds
//to run the sketch
for (int i = 0; i <= sizeof(ledBlink); i++){
digitalWrite(ledBlink[i], HIGH);
delay(duration/2);
digitalWrite(ledBlink[i], LOW);
delay(duration/2);
}
}
//Method to turn Leds off
void turnOff(byte ledOff[]){
for(int i = 0; i <= sizeof(ledOff); i++){
digitalWrite(ledOff[i], LOW);
}
}
//Method to turn Leds On
void turnOn(byte turnOn[]){
for (int i = 0; i <= sizeof(turnOn); i ++){
digitalWrite(turnOn[i], HIGH);
}
}
The serial monitor sends symbols encoded in the ASCII format.
e.g. when you enter 0
, Serial.read()
returns 48
, which is the ASCII code for digit 0
. Since the value 48
is not listed in the following cases, the default branch is taken:
case 0: ...
case 1: ...
case 2: ...
default: ...
There are many solutions to your problem.
1. change case
conditions to match what you are sending:
case '0': ...
case '1': ...
case '2': ...
2. replace Serial.read()
with Serial.parseInt()
:
int ledStatus = Serial.parseInt();
This will actually work with more general inputs, e.g. 123
, but it will return 0
if there is anything different from a digit in the input buffer.
3. wrap Serial.read()
within atoi()
:
byte ledStatus = atoi(Serial.read());
This is somewhat more limited than both of previous options, since now you can only have 10
cases in your switch.