'any' doesn't raise error?

Question

I was playing around then I noticed this:

>>> l = input().split()
1 25 11 4
>>> any(s == s[::-1] for s in l)
True
>>> s == s[::-1] for s in l
SyntaxError: invalid syntax
>>> 

Why does any(s == s[::-1] for s in l) work if s == s[::-1] for s in l itself would raise error?

Answer 1

any(s == s[::-1] for s in l)

is the same as:

any((s == s[::-1] for s in l))

and:

(s == s[::-1] for s in l)

is not a syntax error. It is a generator expression. As you have found parenthesis are required around generator expressions except when they occur as the only argument to a function call.