Problems attaching a function handle on Matlab to integral expression

Question

I have an integral expression which I defined on Matlab using

x = 0:1/1000:1;
g = @(x) (exp(-1./x.^2).*heaviside(x)).*(exp(-1./(1-x).^2).*heaviside(1-x));
t = 0:1/1000:1; 
f = zeros(size(t));
for i = 1:length(t)
    f(i) = integral(g,0,t(i));
end

I can plot it, for example, using plot(t,f), but for other purposes I would like to attach a function handle to f, i.e. something like f = @(t) zeros(size(t)). I have not been able to figure it out thus far. f = @(t) integral(@(x)g(x),0,t) is also not sufficient.

Answer 1

Sorry, I can't comment yet. But does this work?

funcHand= @(t) integral(g,0,t);

You don't have to define x in your code above, since the input to integral is a function handle.

Then to check it's the same:

f2 = zeros(size(t));
for i = 1:length(t)
    f2(i) = funcHand(t(i));
end

Whoops, the other answer said all the above (just replaced the for loop with arrayfun. I didn't see it while writing the answer.

Edit

If you want to build-in the for loop, try:

funcHand= @(t) arrayfun(@(u) integral(g, 0, u),t);

And test:

plot(funcHand(t))