Gorilla mux http package

Question

I'm using Gorilla mux as my router and dispatcher in my golang apps and I have a -I think- simple question:

In my main, I create a router: r := mux.NewRouter(). A few lines further, I register a handler: r.HandleFunc("/", doSomething).

So far so good, but now my problem is that I have a package which adds handlers to the http package of Golang and not to my mux router. Like this:

func AddInternalHandlers() {
    http.HandleFunc("/internal/selfdiagnose.html", handleSelfdiagnose)
    http.HandleFunc("/internal/selfdiagnose.xml", handleSelfdiagnose)
    http.HandleFunc("/internal/selfdiagnose.json", handleSelfdiagnose)
}

As you can see, it adds handles to the http.HandleFunc and not to the mux-handleFunc. Any idea how I can fix this without touching the package itself?

Working example

package main

import (
    "fmt"
    "log"

    "net/http"

    selfdiagnose "github.com/emicklei/go-selfdiagnose"
    "github.com/gorilla/mux"
)

func homeHandler(w http.ResponseWriter, r *http.Request) {
    log.Println("home")
}

func main() {
    r := mux.NewRouter()
    r.HandleFunc("/", homeHandler)

    selfdiagnose.AddInternalHandlers()

  // when handler (nil) gets replaced with mux (r), then the
  // handlers in package selfdiagnose are not "active"
    err := http.ListenAndServe(fmt.Sprintf("%s:%d", "localhost", 8080), nil)
    if err != nil {
        log.Println(err)
    }

}

Answer 1

Well, in your particular case, the solution is easy.

The author of the selfdiagnose package choose to make handlers themselves public, so you can just use them directly:

r.HandleFunc("/", homeHandler)
// use the handlers directly, but you need to name a route yourself
r.HandleFunc("/debug", selfdiagnose.HandleSelfdiagnose)

Working example: https://gist.github.com/miku/9836026cacc170ad5bf7530a75fec777