Filter out array values that do not contain a specified substring

Question

I would like to know how can I filter an array to remove values that do not contain a specified string?

Example:

$array = ['January', 'February', 'March', 'April'];
$to_search = "uary"; // not case sensitivity
$result = somefunction($array, $to_search );
print_r($result);

The expected output is:

$result = ['January', 'February'];

I hope to use the most efficient and fastest way in searching among the arrays because the array that I might use contains at least 100 items.

Answer 1

DEMO

You should choose array_filter function. e.g.

$to_search = "uary"; // not case sensitivity
$array = array('January', 'February', 'March', 'April');

$result = array_filter($array, function ($item) use ($to_search ) {
 if (stripos($item, $to_search ) !== false) {
    return true;
 }
return false;
});

and to get and display your array, use the var_dump

var_dump($result);

Please try with this and let me know.