android: how can I detect when user touch left 20% of view area?

Question

In an activity by using

public boolean dispatchTouchEvent(MotionEvent ev)

how can I know an user is touching left Y-axis of 20% edge area?

It should be generic and orientation handled. I don't want to create any hidden view on that.

Answer 1

• Get device width
• Calculate left 20% width size (from 0 to X)
• Use event.getX()
• Check that event.getX() is inside device with 20%

example :

public class YourActivity extends Activity {

        private LinearLayout background;
        private float xValue, yValue, leftPersentage;
        private int height,width;


        @Override
        protected void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.activity_home);

            DisplayMetrics displaymetrics = new DisplayMetrics();
            getWindowManager().getDefaultDisplay().getMetrics(displaymetrics);
            height = displaymetrics.heightPixels;
            width = displaymetrics.widthPixels;

            leftPersentage = (width)*20/100;

            background = (LinearLayout) findViewById(R.id.background);
            background.setOnTouchListener(new View.OnTouchListener() {
                @Override
                public boolean onTouch(View v, MotionEvent event) {
                    xValue = event.getX();
                    yValue = event.getY();
                    Log.d("Values Clicked" , xValue +"and" + yValue);
                    if(xValue <= leftPersentage){
                        // perform your task 
                        Log.d("Values Clicked onLeft" , xValue +"and" + yValue);
                    }

                    return false;
                }
            });
        }
    }