I'm trying to use sed for parsing log file to extract xml messages from it using the template. I want to get all xml messages in new file.
I'm using this command sed 's/<sending>\(.*\)<\/sending>/\1/' input.out>output.xml
input.out have following сontent:
WARNING: Exchange[ExchangePattern: InOut, BodyType: byte[], Body: <?xml version="1.0" encoding="utf-8" standalone="yes"?><sending><query> <describe> <data>city</data> </describe> </query></sending>]
Sep 26, 2016 11:54:30 AM org.apache.camel.util.CamelLogger log
WARNING: Exchange[ExchangePattern: InOut, BodyType: byte[], Body: <?xml version="1.0" encoding="utf-8" standalone="yes"?><sending> <query> <key_info/> </query></sending>]
I'm expecting to get result like this:
<query> <describe> <data>city</data> </describe> </query> <query> <key_info/> </query>
But i only get source file without <sending> and </sending> elements like this:
WARNING: Exchange[ExchangePattern: InOut, BodyType: byte[], Body: <?xml version="1.0" encoding="utf-8" standalone="yes"?><query> <describe> <data>city</data> </describe> </query>]
Sep 26, 2016 11:54:30 AM org.apache.camel.util.CamelLogger log
WARNING: Exchange[ExchangePattern: InOut, BodyType: byte[], Body: <?xml version="1.0" encoding="utf-8" standalone="yes"?> <query> <key_info/> </query>]
Sorry for my english and have a nice day. Thank you for help.
sed 's/.*<sending>\(.*\)<\/sending>.*/\1/' input.out>output.xml
you forget to remove surrounding part of the line (.*), sed only take the content of your pattern and you don't include char before or after your sending bloc
now i suggest
sed -e '/.*<sending>\(.*\)<\/sending>.*/!d' -e 's//\1/' input.out>output.xml
it remove line that don't have the sending bloc. Don't forget that sed take the longest partterne available so if there are 2 bloc on same line (or more) it take from first sending until last /sending