Zipping files with apache camel

Question

i am saving files on path C:\Cdr\core\year\month\date\fileName and i want to zip all the files created on previous day and before that.I am unable to find a way to provide dynamic file path and file name to file Consumer for zipping files. Even when using filename=${beans:utility.generateFileName}, i am only able to provide file name not the file path.Is there a way to do this using apache Zip file data format.

Answer 1

I found the way for same by using filter

<routeContext id="zipFileRoute" xmlns="http://camel.apache.org/schema/spring">
  <route id="zipFile">
    <from uri="file://C:/CdrJson?recursive=true&amp;delete=true&amp;filter=#myFilter/>
    <log message="reading from ${in.header.CamelFileName} and file path is ${file:path}"/>
    <setHeader headerName="CamelFileName">
      <simple>${bean:utility?method=processFileName}</simple>
    </setHeader>
    <marshal>
      <zipFile/>
    </marshal>
    <to uri="file://C:/CdrJson"/>
    <log message="This route finished zipping files"/>
  </route>
</routeContext>

Code for myFilter:

public class MyFileFilter<T> implements GenericFileFilter<T> {
  public boolean accept(GenericFile<T> file) { 
    // we want all directories
    if (file.isDirectory()) {
      return true;
    }
    Calendar date = new GregorianCalendar();
    String fileName = new SimpleDateFormat("yyyy-MM-dd").format(new Date());
    if(file.getFileNameOnly().startsWith(fileName)){
      return false;
    }
    return !file.getFileName().endsWith(".zip");
  }
}