I have this code:
$link ="<a href=http://www.gamingpopulace.com/threads/index?threadName='".$inputLocation."'>$inputLocation</a>";
$inputLocation= New Game Excitement
But only the first word of the variable is passed into $link, in this case "New". I know this is caused by not properly quoting the variable, but if I add any quotes around it now, an error is caused.
How do I pass all the words in the $inputLocation variable into the $link variable?
Thanks
You don't want to quote the variable, you want to URL-encode it. Something like this:
$link = '<a href="http://www.gamingpopulace.com/threads/index?threadName=' . urlencode($inputLocation) . '">' . $inputLocation . '</a>';
Note: This example also fixes a quoting issue you have where, while trying to quote the value, you weren't quoting the href
attribute itself. In doing so I also swapped the usage of single-quotes and double-quotes since HTML attributes should be double-quoted.