How to emulate C++ `x=x&&f()` in bash

Question

I'm writing this all over the place:

if (( $x == 0 )) ; then
    mycommand
    x=$?
fi

Is there a simpler/briefer way to do this with bash's short-circuiting &&?

EDIT: I don't care about the value of $x other than it's zeroness i.e. success/failure.

Answer 1

So, variable x is just the result of the previous command? If you mean that you have a continuous series of almost identical blocks like:

if (( $x == 0 )) ; then my_command_1; x=$?; fi
....
if (( $x == 0 )) ; then my_command_N; x=$?; fi

Then, just combine your commands this way

my_command_1 \
&& ... \
&& my_command_N

[update]

On the other hand, if the commands are scattered all over the script, I would do either:

x=true
$x && my_command_1 || x=false
...
$x && my_command_2 || x=false

Or, more discreet:

$do my_command_1 || do=:
...
$do my_command_2 || do=:

Or, more probably, through a function:

function check_and_do { [ -z "$failed" ] && "$@" || failed=ouch; }

check_and_do my_command_1
....
check_and_do my_command_2