I am trying to open an image with subprocess so it is visible to the user, then close the image so that it disapears.
This question has been asked before, but the answers I found have not worked for me. Here is what I have checked:
Killing a process created with Python's subprocess.Popen()
How to terminate a python subprocess launched with shell=True
How can I close an image shown to the user with the Python Imaging Library?
I need the code to open an image (with Preview (optional), default on my Mac), wait a second, then close the image.
openimg = subprocess.Popen(["open", mypath])
time.sleep(1)
openimg.terminate()
openimg.kill()
Everything is telling me to terminate() and kill(), but that still isn't closing the image.
This does not HAVE to use preview, I am open to hearing other options as well.
Edit: I have additionally tried the below code, still no success
print('openimg\'s pid = ',openimg.pid)
os.kill(openimg.pid, signal.SIGKILL)
I'm sure this is the hackiest way to do this, but hell, it works. If anyone stumbles on this and knows a better way, please let me know.
The Problem As David Z described, I was not targeting the correct process. So I had to figure out what the correct process ID was in order to close it properly.
I started by opening my terminal and entering the command ps -A. This will show all of the current open processes and their ID. Then I just searched for Preview and found two open processes.
Previously, I was closing the first Preview pid in the list, let's call it 11329 but the second on the list was still open. The second Preview process, 11330, was always 1 digit higher then the first process. This second one was the pid I needed to target to close Preview.
The Answer
openimg = subprocess.Popen(["open", mypath]) ##Opens the image to view
newpid = openimg.pid + 1 ##Gets the pid 1 digit higher than the openimg pid.
os.kill(newpid, signal.SIGKILL) ##Kills the pid and closes Preview
This answer seems very fragile, but it works for me. I only just started learning about pids so if anyone could provide some knowledge, I would be grateful.